document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1200603>Question 1200603</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A distribution of values is normal with a mean of 40 and a standard deviation of 98.\r<BR>\n" );
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document.write( "Find P39, which is the score separating the bottom 39% from the top 61%.<BR>\n" );
document.write( "P39 = \r<BR>\n" );
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document.write( "Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.the same aptitude, but use different scales. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #848069 by </B><A HREF=/tutors/aboutme.mpl?userid=GingerAle><B>GingerAle(43)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=GingerAle><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=848069\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> **1. Find the z-score corresponding to P39:**\r<BR>\n" );
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document.write( "* P39 means the 39th percentile. <BR>\n" );
document.write( "* We need to find the z-score that corresponds to the area below it in the standard normal distribution table. <BR>\n" );
document.write( "* Using a standard normal distribution table or a calculator, we find that the z-score corresponding to the 39th percentile is approximately **-0.279**.\r<BR>\n" );
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document.write( "**2. Calculate P39:**\r<BR>\n" );
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document.write( "* Use the formula: <BR>\n" );
document.write( "   * P39 = μ + (z-score * σ) <BR>\n" );
document.write( "   * where μ is the mean and σ is the standard deviation.\r<BR>\n" );
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document.write( "* P39 = 40 + (-0.279 * 98) <BR>\n" );
document.write( "* P39 = 40 - 27.302<BR>\n" );
document.write( "* P39 ≈ 12.7\r<BR>\n" );
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document.write( "**Therefore, P39 is approximately 12.7.**<BR>\n" );
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