document.write( "Question 1209278: Find the area of the region enclosed by the graph of x^2 + y^2 = 2x - 6y + 6. \n" ); document.write( "
Algebra.Com's Answer #848052 by ikleyn(52800)\"\" \"About 
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\n" ); document.write( "Find the area of the region enclosed by the graph of x^2 + y^2 = 2x - 6y + 6.
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document.write( "Write the given equation in the standard form of the ellipse/circle equation\r\n" );
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document.write( "    x^2 + y^2 = 2x - 6y + 6,\r\n" );
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document.write( "    x^2 -2x + y^2 + 6x = 6,\r\n" );
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document.write( "    (x^2 - 2x + 1) + (y^2 + 6x + 9) = 6 + 1 + 9,\r\n" );
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document.write( "    (x-1)^2 + (y+3)^2 = 16.\r\n" );
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document.write( "This equation represents a circle of the radius  r = \"sqrt%2816%29\" = 4.  centered at point (1,-3).\r\n" );
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document.write( "The area of this circle is  \r\n" );
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document.write( "    \"pi%2Ar%5E2\"  = \"16%2Api\" = 16*3.14159265 = 50.2654824 square units (approximately).    ANSWER\r\n" );
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