document.write( "Question 1209254: Kylan is four times as old as Ella. Quentin is one year younger than Kylan and five years older than Ella.
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Algebra.Com's Answer #847923 by ikleyn(52788) $\"\"$ $\"About$

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document.write( "Let x be the Ella's age, in years.\r\n" );
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document.write( "Then Kylan age is 4x years.\r\n" );
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document.write( "Quentin age is, from one side, 4x-1 years,\r\n" );
document.write( "and from the other side, x+5 years.\r\n" );
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document.write( "It gives this equation\r\n" );
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document.write( "    4x - 1 = x + 5.\r\n" );
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document.write( "Solve it, step by step\r\n" );
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document.write( "    4x - x = 5 + 1\r\n" );
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document.write( "      3x   =   6\r\n" );
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document.write( "       x   =   6/3 = 2.\r\n" );
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document.write( "ANSWER.  Ella is 2 years old;  Kylan is 4*2 = 8 years old;  Quentin is 8-1 = 7 years old.\r\n" );
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