document.write( "Question 1209240: A biologist is researching a newly discovered species of bacteria. At time T equals zero hours, he put 100 bacteria into what he has determined to be a favorable growth medium. Six hours later, he measures 450 bacteria. Assuming exponential growth, what is the growth constant K for the bacteria? (Round K2 decimal places) By what hour to the nearest 10 will there be 1000 bacteria? \n" ); document.write( "
Algebra.Com's Answer #847904 by timofer(105)\"\" \"About 
You can put this solution on YOUR website!
You could choose this form for the growth model:
\n" ); document.write( "\"p=a%2Ae%5E%28Kx%29\"\r
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\n" ); document.write( "\n" ); document.write( "Your given starting information means, by substitution,
\n" ); document.write( "\"450=100e%5E%286K%29\"\r
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\n" ); document.write( "\n" ); document.write( "Take natural log of both sides.
\n" ); document.write( "\"ln%28450%29=ln%28100%29%2B6K%2Aln%28e%29\"
\n" ); document.write( "\"ln%28450%29-ln%28100%29=6K\"\r
\n" ); document.write( "\n" ); document.write( "\"K=%28ln%28450%29-ln%28100%29%29%2F6\"
\n" ); document.write( "and you can compute this...
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