document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1209231>Question 1209231</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number of ways to arrange the seating of four men and their wives around a circle, so that each man remains adjacent to his wife, equals...\"\r<BR>\n" );
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document.write( "Followed by the multiple-choice options:\r<BR>\n" );
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document.write( "48<BR>\n" );
document.write( "96<BR>\n" );
document.write( "120<BR>\n" );
document.write( "384 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #847877 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=847877\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "(1) Treat each husband-wife pair as a single unit.  You then have four things to arrange around the table.<br><BR>\n" );
document.write( "(2) If they were being arranged in a line, the number of ways of arranging them would be 4*3*2*1 = 4! = 24.  But since they are being arranged around a table, there are four possible \"starting points\" for the arrangement, so the number of ways to arrange the four groups around a table is 24/4 = 6.  (In general, there are (n!) ways of arranging n things in a line and ((n-1)!) ways of arranging n items in a circular pattern.)<br><BR>\n" );
document.write( "(3) Within each of the four groups, the man and woman can be in either of two orders.<br><BR>\n" );
document.write( "ANSWER: (6)(2)(2)(2)(2) = 96<br><BR>\n" );
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