document.write( "Question 1209228: Let a and b be the roots of the quadratic 2x^2 - 8x + 7 = -3x^2 + 15x + 11. Compute 1/a^2 + 1/b^2. \n" ); document.write( "
Algebra.Com's Answer #847876 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answer: 569/16
\n" ); document.write( "569/16 = 35.5625 exactly without any rounding done to it.\r
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\n" ); document.write( "\n" ); document.write( "Explanation\r
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\n" ); document.write( "\n" ); document.write( "2x^2 - 8x + 7 = -3x^2 + 15x + 11
\n" ); document.write( "rearranges to
\n" ); document.write( "5x^2 - 23x - 4 = 0
\n" ); document.write( "after getting everything to one side.\r
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\n" ); document.write( "\n" ); document.write( "Divide everything by the leading coefficient
\n" ); document.write( "x^2 - (23/5)x - 4/5 = 0
\n" ); document.write( "This is to make the leading coefficient be equal to 1.\r
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\n" ); document.write( "\n" ); document.write( "Vieta's Formulas say that the roots add to the negative of the x coefficient while also multiplying to the constant term when the leading coefficient is 1.
\n" ); document.write( "So we can establish these equations
\n" ); document.write( "a+b = 23/5
\n" ); document.write( "a*b = -4/5\r
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\n" ); document.write( "\n" ); document.write( "Let's square both sides of the first equation
\n" ); document.write( "a+b = 23/5
\n" ); document.write( "(a+b)^2 = (23/5)^2
\n" ); document.write( "a^2+2ab+b^2 = 529/25
\n" ); document.write( "a^2+2*(-4/5)+b^2 = 529/25 ......... plug in ab = -4/5
\n" ); document.write( "a^2-8/5+b^2 = 529/25
\n" ); document.write( "a^2+b^2 = 529/25+8/5
\n" ); document.write( "a^2+b^2 = 529/25+40/25
\n" ); document.write( "a^2+b^2 = 569/25
\n" ); document.write( "The motivation for this paragraph of algebra might not be obvious until reaching the next section below.\r
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\n" ); document.write( "\n" ); document.write( "Then,
\n" ); document.write( "\"c+=+1%2F%28a%5E2%29+%2B+1%2F%28b%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"c%2A%28ab%29%5E2+=+%281%2F%28a%5E2%29+%2B+1%2F%28b%5E2%29%29%2A%28ab%29%5E2\" Multiplying both sides by the LCD to clear out the fractions\r
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\n" ); document.write( "\n" ); document.write( "\"c%2A%28ab%29%5E2+=+b%5E2+%2B+a%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"c%2A%28-4%2F5%29%5E2+=+569%2F25\"\r
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\n" ); document.write( "\n" ); document.write( "\"c%2A%2816%2F25%29+=+569%2F25\"\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28569%2F25%29%2A%2825%2F16%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+569%2F16\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%28a%5E2%29+%2B+1%2F%28b%5E2%29+=+569%2F16\"\r
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\n" ); document.write( "\n" ); document.write( "I used GeoGebra to verify the answer is correct.
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