document.write( "Question 1209054: The four sides and one diagonal of a rhombus each have sides 3√6 cm long. Find the area of the rhombus, in cm^2.
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Algebra.Com's Answer #847869 by MathTherapy(10552)\"\" \"About 
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document.write( "The four sides and one diagonal of a rhombus each have sides 3√6 cm long. Find the area of the rhombus, in cm^2.\r\n" );
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document.write( "Since one of its diagonals is equal to its sides, then 2 EQUILATERAL triangles will emerge, to form the rhombus\r\n" );
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document.write( "Each angle of each equilateral triangle = \"180%2F3\" = 60o\r\n" );
document.write( "Area of any NON-RIGHT triangle = \"1%2F2\" the PRODUCT of 2 of its CONSECUTIVE sides, TIMES the sine of the INCLUDED angle \r\n" );
document.write( "So, AREA of one of this rhombus' 2 equilateral triangles = \"%281%2F2%293sqrt%286%29+%2A+3sqrt%286%29+%2A+sin+60%5Eo\" = \"%281%2F2%29%283sqrt%286%29%29%5E2%2Asin+60%5Eo\" \r\n" );
document.write( "                                                                                   --- Substituting \"sqrt%283%29%2F2%29\" for sin 60o\r\n" );
document.write( "As there are 2 of these equilateral triangles, AREA of both equilateral triangles/RHOMBUS = \"2%2827%28sqrt%283%29%2F2%29%29%29\" = \"cross%282%29%2827%28sqrt%283%29%2Fcross%282%29%29%29%29\" =
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