document.write( "Question 1209224: If 2x-3y = 5, then find (9^x)/(27^y) = ?? \n" ); document.write( "
Algebra.Com's Answer #847864 by math_tutor2020(3816)\"\" \"About 
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\n" ); document.write( "Answer: 243\r
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\n" ); document.write( "\n" ); document.write( "Work Shown\r
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\n" ); document.write( "\n" ); document.write( "(9^x)/(27^y)
\n" ); document.write( "= ((3^2)^x)/((3^3)^y)
\n" ); document.write( "= (3^(2x))/(3^(3y))
\n" ); document.write( "= 3^(2x-3y)
\n" ); document.write( "= 3^(5)
\n" ); document.write( "= 243\r
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\n" ); document.write( "\n" ); document.write( "We conclude that (9^x)/(27^y) = 243 when 2x-3y = 5.\r
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\n" ); document.write( "Another approach.\r
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\n" ); document.write( "\n" ); document.write( "Pick any point on the line 2x-3y = 5.
\n" ); document.write( "Let's say we pick the point (x,y) = (4,1).
\n" ); document.write( "You can determine this point by looking at the graph, or do a bit of trial-and-error. \r
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\n" ); document.write( "\n" ); document.write( "Note that 2x-3y = 2*4-3*1 = 8-3 = 5 which confirms (4,1) is on this line.
\n" ); document.write( "This ordered pair makes 2x-3y = 5 true.\r
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\n" ); document.write( "\n" ); document.write( "(9^x)/(27^y)
\n" ); document.write( "= (9^4)/(27^1)
\n" ); document.write( "= (6561)/(27)
\n" ); document.write( "= 243
\n" ); document.write( "We arrive at the same answer.
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