document.write( "Question 1209216: Fill in the blanks to make a quadratic whose roots are -5 and 5.\r
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document.write( "x^2 + ___ x + ___ \n" );
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Algebra.Com's Answer #847859 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "If -5 and 5 are the roots of this monic polynomial, then (x+5) and (x-5) are factors\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x+5)(x-5) = x^2 - 25 due to the difference of squares rule.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore the answer is: \n" ); document.write( " x^2 + 0 x + -25 \n" ); document.write( "--------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another approach.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's say the blanks are b and c for now.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We have x^2+bx+c\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If p,q are the roots of this quadratic, then (x-p) and (x-q) are factors.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-p)(x-q) = x^2-qx-px+pq \n" ); document.write( "(x-p)(x-q) = x^2-(p+q)x+pq\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We have \n" ); document.write( "x^2+bx+c = x^2-(p+q)x+pq\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Comparing terms shows that \n" ); document.write( "-(p+q)x = bx which leads to b = -(p+q) \n" ); document.write( "and, \n" ); document.write( "c = pq\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In short, \n" ); document.write( "b = -(p+q) \n" ); document.write( "c = pq \n" ); document.write( "Which are part of Vieta's Formulas.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In this case the roots are p = -5 and q = 5 \n" ); document.write( "b = -(p+q) = -(-5+5) = 0 \n" ); document.write( "c = p*q = -5*5 = -25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We arrive at the answer \n" ); document.write( " x^2 + 0 x + -25 \n" ); document.write( " \n" ); document.write( " |