document.write( "Question 1209216: Fill in the blanks to make a quadratic whose roots are -5 and 5.\r
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Algebra.Com's Answer #847849 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Notice that the leading coefficient at x^2 is 1.\r\n" );
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document.write( "Apply the Vieta's theorem, which says that the sum of the roots \r\n" );
document.write( "of such quadratic equation is the coefficient at x with the opposite sign,\r\n" );
document.write( "while the product of the roots is the constant terms.\r\n" );
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document.write( "It gives you the coefficient at x  of  -((-5)+5) = -0 = 0\r\n" );
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document.write( "and the constant term of (-5)*5 = -25.\r\n" );
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document.write( "Therefore, the restored equation is  x^2 + 0*x - 25 = 0,  or simply  x^2 - 25 = 0.\r\n" );
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document.write( "ANSWER.  First blank (the coefficient at x) is  0  (zero).\r\n" );
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document.write( "         Second blank (the constant term) is  -25.\r\n" );
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