document.write( "Question 1209209: Given that x = 2ᵅ and y = 4ⁿ, show clearly that log₂(x²y) = 3α + 2n \n" ); document.write( "
Algebra.Com's Answer #847841 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Log Rules
\n" ); document.write( "log(M*N) = log(M)+log(N)
\n" ); document.write( "log(M^N) = N*log(M)
\n" ); document.write( "Let's refer to these as equations (1) and (2)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+2%5Ea\" converts to the log form \"log%282%2C%28x%29%29+=+a\"
\n" ); document.write( "I'll refer to this as equation (3)\r
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\n" ); document.write( "\n" ); document.write( "Also,
\n" ); document.write( "\"y+=+4%5En\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%282%5E2%29%5En\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+2%5E%282n%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2C%28y%29%29+=+2n\" Let's call this equation (4)\r
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\n" ); document.write( "\n" ); document.write( "Then we would write the following
\n" ); document.write( "\"log%282%2C%28x%5E2y%29%29+=+log%282%2C%28x%5E2%29%29%2Blog%282%2C%28y%29%29\" Use equation (1)\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2C%28x%5E2y%29%29+=+2%2Alog%282%2C%28x%29%29%2Blog%282%2C%28y%29%29\" Use equation (2)\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2C%28x%5E2y%29%29+=+2a%2Blog%282%2C%28y%29%29\" Use equation (3)\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2C%28x%5E2y%29%29+=+2a%2B2n\" Use equation (4)\r
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\n" ); document.write( "\n" ); document.write( "I don't know where your teacher is getting the 3 in 3a.
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