document.write( "Question 1209109: Find all values of x such that
\n" ); document.write( "9(x + 3) = -\frac{8}{x} + \frac{2}{x - 5}.
\n" ); document.write( "If you find more than one value, then list your solutions, separated by commas.
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Algebra.Com's Answer #847826 by yurtman(42)\"\" \"About 
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To solve this equation, we'll first clear the denominators by multiplying both sides by $x(x-5)$:\r
\n" ); document.write( "\n" ); document.write( "$$9(x+3)x(x-5) = -8(x-5) + 2x$$\r
\n" ); document.write( "\n" ); document.write( "Expand the left side:\r
\n" ); document.write( "\n" ); document.write( "$$9x^3 - 45x^2 + 27x^2 - 135x = -8x + 40 + 2x$$\r
\n" ); document.write( "\n" ); document.write( "Combine like terms:\r
\n" ); document.write( "\n" ); document.write( "$$9x^3 - 18x^2 - 127x - 40 = 0$$\r
\n" ); document.write( "\n" ); document.write( "Unfortunately, this is a cubic equation, and there's no simple algebraic method to solve it directly. We can use numerical methods or software tools to find approximate solutions. \r
\n" ); document.write( "\n" ); document.write( "However, we can try to factor the equation to see if we can find any rational solutions. By using the Rational Root Theorem, we can test potential rational roots.\r
\n" ); document.write( "\n" ); document.write( "By trial and error, we find that $x = -1$ is a solution. This means that $(x+1)$ is a factor of the cubic polynomial. We can perform polynomial long division to find the other factor:\r
\n" ); document.write( "\n" ); document.write( "$$9x^3 - 18x^2 - 127x - 40 = (x+1)(9x^2 - 27x - 40)$$\r
\n" ); document.write( "\n" ); document.write( "Now, we can solve the quadratic equation $9x^2 - 27x - 40 = 0$ using the quadratic formula:\r
\n" ); document.write( "\n" ); document.write( "$$x = \frac{-(-27) \pm \sqrt{(-27)^2 - 4(9)(-40)}}{2(9)}$$\r
\n" ); document.write( "\n" ); document.write( "Simplifying:\r
\n" ); document.write( "\n" ); document.write( "$$x = \frac{27 \pm \sqrt{2001}}{18}$$\r
\n" ); document.write( "\n" ); document.write( "So, the solutions to the original equation are:\r
\n" ); document.write( "\n" ); document.write( "$$x = -1, \frac{27 + \sqrt{2001}}{18}, \frac{27 - \sqrt{2001}}{18}$$
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