document.write( "Question 1209068: Solve 3a + 4b = 5a - 6b + 24 + a/(b^3 - 7b + 24) for a in terms of b. \n" ); document.write( "
Algebra.Com's Answer #847824 by yurtman(42)\"\" \"About 
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To solve for `a`, we'll first group the terms involving `a` on one side of the equation:\r
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\n" ); document.write( "3a + 4b = 5a - 6b + 24 + a/(b^3 - 7b + 24)
\n" ); document.write( "3a - 5a - a/(b^3 - 7b + 24) = 24 - 6b - 4b
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\n" ); document.write( "\n" ); document.write( "Combine like terms:\r
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\n" ); document.write( "-3a - a/(b^3 - 7b + 24) = 24 - 10b
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\n" ); document.write( "\n" ); document.write( "Factor out `a` on the left side:\r
\n" ); document.write( "\n" ); document.write( "```
\n" ); document.write( "a(-3 - 1/(b^3 - 7b + 24)) = 24 - 10b
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\n" ); document.write( "\n" ); document.write( "To isolate `a`, divide both sides by the factor `(-3 - 1/(b^3 - 7b + 24))`:\r
\n" ); document.write( "\n" ); document.write( "```
\n" ); document.write( "a = (24 - 10b) / (-3 - 1/(b^3 - 7b + 24))
\n" ); document.write( "```\r
\n" ); document.write( "\n" ); document.write( "To simplify the complex fraction, we can multiply the numerator and denominator by `(b^3 - 7b + 24)`:\r
\n" ); document.write( "\n" ); document.write( "```
\n" ); document.write( "a = [(24 - 10b)(b^3 - 7b + 24)] / [(-3)(b^3 - 7b + 24) - 1]
\n" ); document.write( "```\r
\n" ); document.write( "\n" ); document.write( "Expanding the numerator and simplifying the denominator:\r
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\n" ); document.write( "a = (24b^3 - 168b + 576 - 10b^4 + 70b^2 - 240b) / (-3b^3 + 21b - 72 - 1)
\n" ); document.write( "```\r
\n" ); document.write( "\n" ); document.write( "Combining like terms:\r
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\n" ); document.write( "a = (-10b^4 + 24b^3 + 70b^2 - 408b + 576) / (-3b^3 + 21b - 73)
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\n" ); document.write( "\n" ); document.write( "So, the solution for `a` in terms of `b` is:\r
\n" ); document.write( "\n" ); document.write( "```
\n" ); document.write( "a = (-10b^4 + 24b^3 + 70b^2 - 408b + 576) / (-3b^3 + 21b - 73)
\n" ); document.write( "```
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