document.write( "Question 1208986: A tight end can run the 100-yard dash in 12 seconds. A defensive back can do it in 10 seconds. The tight end catches a pass at his own 20-yard line with the defensive back at the 15-yard line. If no other players are nearby, at what yard line will the defensive back catch up to the tight end?\r
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document.write( "Hint: At time t = 0, the defensive back is 5 yards behind the tight end. \r
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Algebra.Com's Answer #847805 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: tight end's own 45 yard line\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "TE = tight end \n" ); document.write( "DB = defensive back\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's find the TE's speed \n" ); document.write( "distance = rate*time \n" ); document.write( "d = r*t \n" ); document.write( "r = d/t \n" ); document.write( "r = (100 yards)/(12 seconds) \n" ); document.write( "r = (100/12) yards per second \n" ); document.write( "r = (25/3) yards per second \n" ); document.write( "r = 8.3333 yards per second approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "DB's speed \n" ); document.write( "r = d/t \n" ); document.write( "r = (100 yards)/(10 seconds) \n" ); document.write( "r = (100/10) yards per second \n" ); document.write( "r = 10 yards per second\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "After x number of seconds, the TE travels a distance of (25/3)x yards. \n" ); document.write( "Meanwhile the DB travels 10x yards.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The gap between the players is initially 5 yards. \n" ); document.write( "Whatever distance the TE travels, the DB must travel that distance plus 5 extra yards to catch up. \n" ); document.write( "For example, if the TE travels 10 yards, then the DB must travel 10+5 = 15 yards to catch up to the TE.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "DB's travel distance = (TE's travel distance) + 5 yards \n" ); document.write( "10x = (25/3)x+5 \n" ); document.write( "3*10x = 3*( (25/3)x+5 ) \n" ); document.write( "30x = 25x+15 \n" ); document.write( "30x-25x = 15 \n" ); document.write( "5x = 15 \n" ); document.write( "x = 15/5 \n" ); document.write( "x = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The DB catches the TE at exactly the x = 3 second timestamp. \n" ); document.write( "The DB catches (and perhaps tackles) the TE exactly 3 seconds after the TE caught the ball. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "After 3 seconds elapse, the TE traveled (25/3)*x = (25/3)*3 = 25 yards. \n" ); document.write( "The TE goes from the 20 yard line to the 20+25 = 45 yard line. \n" ); document.write( "The TE has not crossed the midway marker since 45 < 50. \n" ); document.write( "Therefore the TE is still on his side of the field.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Meanwhile the DB runs 10*x = 10*3 = 30 yards \n" ); document.write( "The DB goes from the 15 yard line to the 15+30 = 45 yard line \n" ); document.write( " \n" ); document.write( " |