document.write( "Question 1209190: solve the simultaneous Equations 3a^2 - 4y = -1, 2a - y = 1 \n" ); document.write( "

Algebra.Com's Answer #847790 by ikleyn(52786) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "solve the simultaneous Equations 3a^2 - 4y = -1, 2a - y = 1
\n" ); document.write( "~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "From the second equation, express  y = 2a-1  and substitute it into first equation.\r\n" );
document.write( "You will get\r\n" );
document.write( "\r\n" );
document.write( "    3a^2 - 4(2a-1) = -1,\r\n" );
document.write( "\r\n" );
document.write( "    3a^2 - 8a + 4 = -1,\r\n" );
document.write( "\r\n" );
document.write( "    3a^2 - 8a + 5 = 0,\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "apply the quadratic formula\r\n" );
document.write( "\r\n" );
document.write( "     =  = .\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "So, there are two options for \"a\": they are\r\n" );
document.write( "\r\n" );
document.write( "    a =  =   and  a = 1.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Now find y for each value of \"a\", using y = 2a-1.\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "From this point, can you complete on your own ?\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );