document.write( "Question 1209188: The first and last terms of an A.P are 1 and 121 respectively. Find
\n" ); document.write( "(a) the number of terms in the A.P
\n" ); document.write( "(b) the commons difference if the sum of its term is 671
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Algebra.Com's Answer #847789 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "n = number of terms
\n" ); document.write( "d = common difference
\n" ); document.write( "a1 = first term = 1
\n" ); document.write( "an = nth term = 121\r
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\n" ); document.write( "\n" ); document.write( "Sn = sum of the first n terms of an arithmetic sequence
\n" ); document.write( "Sn = (n/2)*(a1+an)
\n" ); document.write( "671 = (n/2)*(1+121)
\n" ); document.write( "671 = (n/2)*122
\n" ); document.write( "671 = 61n
\n" ); document.write( "n = 671/61
\n" ); document.write( "n = 11
\n" ); document.write( "There are 11 terms in this arithmetic sequence.\r
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\n" ); document.write( "\n" ); document.write( "an = nth term
\n" ); document.write( "an = a1 + d*(n-1)
\n" ); document.write( "a11 = 1 + d*(11-1)
\n" ); document.write( "121 = 1 + d*(11-1)
\n" ); document.write( "121 = 1 + 10d
\n" ); document.write( "10d = 121-1
\n" ); document.write( "10d = 120
\n" ); document.write( "d = 120/10
\n" ); document.write( "d = 12
\n" ); document.write( "The common difference is 12
.\r
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\n" ); document.write( "\n" ); document.write( "The arithmetic sequence is: 1, 13, 25, 37, 49, 61, 73, 85, 97, 109, 121
\n" ); document.write( "I used GeoGebra to generate the sequence quickly. You can also use a spreadsheet to generate the list.
\n" ); document.write( "The sum of these values is 671 to help confirm the answers are correct.
\n" ); document.write( "I don't recommend manually typing 1+13+25+37+49+61+73+85+97+109+121 into a calculator such as a TI83 since it would be tedious busy-work.\r
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\n" ); document.write( "\n" ); document.write( "Answers:
\n" ); document.write( "(a) 11 terms
\n" ); document.write( "(b) common difference is 12
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