document.write( "Question 1209156: In the diagram, BD=15 cm and DC=6 cm. Find the ratio of the area of the parallelogram to the area of Triangle ABC.
\n" );
document.write( "https://ibb.co/MDp9vC7 \n" );
document.write( "
Algebra.Com's Answer #847747 by greenestamps(13215) You can put this solution on YOUR website! \n" ); document.write( "EF and DC are congruent. \n" ); document.write( "With all the given parallel line segments, triangles AEF, EBD, and ABC are all similar. \n" ); document.write( "Corresponding sides EF, BD, and BC of those three triangles have lengths 6, 15, and 21, so the ratio of similarity among the three triangles is 6:15:21, or 2:5:7. \n" ); document.write( "The ratio of the areas of the three triangles is the square of the ratio of similarity, which is 4:25:49. \n" ); document.write( "For convenience, let the areas of the three triangles be... \n" ); document.write( "AEF = 4x \n" ); document.write( "EBD = 25x \n" ); document.write( "ABC = 49x \n" ); document.write( "The parallelogram is triangle ABC, minus triangles AEF and EBD, so the area of the parallelogram is 49x-4x-25x = 20x. So the ratio of the area of the parallelogram to the area of triangle ABC is 20x:49x = 20:49. \n" ); document.write( "ANSWER: 20:49 \n" ); document.write( " \n" ); document.write( " |