document.write( "Question 1209156: In the diagram, BD=15 cm and DC=6 cm. Find the ratio of the area of the parallelogram to the area of Triangle ABC.
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Algebra.Com's Answer #847747 by greenestamps(13215)\"\" \"About 
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\n" ); document.write( "EF and DC are congruent.

\n" ); document.write( "With all the given parallel line segments, triangles AEF, EBD, and ABC are all similar.

\n" ); document.write( "Corresponding sides EF, BD, and BC of those three triangles have lengths 6, 15, and 21, so the ratio of similarity among the three triangles is 6:15:21, or 2:5:7.

\n" ); document.write( "The ratio of the areas of the three triangles is the square of the ratio of similarity, which is 4:25:49.

\n" ); document.write( "For convenience, let the areas of the three triangles be...
\n" ); document.write( "AEF = 4x
\n" ); document.write( "EBD = 25x
\n" ); document.write( "ABC = 49x

\n" ); document.write( "The parallelogram is triangle ABC, minus triangles AEF and EBD, so the area of the parallelogram is 49x-4x-25x = 20x. So the ratio of the area of the parallelogram to the area of triangle ABC is 20x:49x = 20:49.

\n" ); document.write( "ANSWER: 20:49

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