document.write( "Question 1209159: In the diagram, ABCG is a parallelogram, and BF = 18 cm, FE = 6 cm. Find the length, in cm, of ED.
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Algebra.Com's Answer #847745 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Angles AEF and CBF are congruent (parallel lines cut by a transversal).
\n" ); document.write( "Likewise angles EAF and BCF are congruent.

\n" ); document.write( "So triangles AEF and CBF are similar; and legs EF and BF, for which lengths are given, are corresponding parts of those similar triangles.

\n" ); document.write( "Since those lengths are 18 and 6, the ratio of similarity between the two triangles is 3:1.

\n" ); document.write( "That means BC is 3 times the length of AE; and that means EG is twice the length of AE.

\n" ); document.write( "Angles BAG and AGC are supplementary (adjacent angles in parallelogram ABCG), so angles AGD and BAE are congruent.

\n" ); document.write( "That makes triangles BAE and DGE similar; and with EG twice AE, the ratio of similarity between those two triangles is 2:1.

\n" ); document.write( "And BE, with length 18+6=24, and ED are corresponding parts of those two triangles, so the length of ED is twice the length of BE, or 2*24 = 48.

\n" ); document.write( "ANSWER: 48

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