document.write( "Question 1209150: Find all real values of s such that x^2 + sx + 144 - 6x + 3x^2 is the square of a binomial. \n" ); document.write( "
Algebra.Com's Answer #847731 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "\"x%5E2+%2B+sx+%2B+144+-+6x+%2B+3x%5E2\" = \"4x%5E2%2B%28s-6%29x%2B144\"

\n" ); document.write( "In the simplified polynomial, the leading term is \"4x%5E2\", so the leading term of the square root is \"sqrt%284x%5E2%29\" = \"2x\".

\n" ); document.write( "The constant term of the simplified polynomial is 144, so the constant term of the square root is \"sqrt%28144%29\" = \"12\".

\n" ); document.write( "So the possible square root polynomials are \"2x%2B12\" and \"2x-12\".

\n" ); document.write( "\"%282x%2B12%29%5E2+=+4x%5E2%2B48x%2B144\" so for one solution we have

\n" ); document.write( "\"s-6=48\" --> \"s=54\"

\n" ); document.write( "\"%282x-12%29%5E2+=+4x%5E2-48x%2B144\" so for a second solution we have

\n" ); document.write( "\"s-6=-48\" --> \"s=-42\"

\n" ); document.write( "ANSWERS: s=54 and s=-42

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