document.write( "Question 1209114: A box has a certain length, width, and height. The length of the box is equal to twice its width, as well as equal to 8 less than its height. If the total surface area of the box is 480, then what is the height of the box? \n" ); document.write( "
Algebra.Com's Answer #847693 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answer:
\n" ); document.write( "exact height = 5 + sqrt(129)
\n" ); document.write( "approximate height = 16.357816691601\r
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\n" ); document.write( "\n" ); document.write( "Work Shown\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"length is twice the width\" ---> \"width is half the length\".
\n" ); document.write( "\"length is 8 units smaller than the height\" ---> \"height is 8 units longer compared to length\".
\n" ); document.write( "x = length
\n" ); document.write( "x/2 = 0.5x = width
\n" ); document.write( "x+8 = height\r
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\n" ); document.write( "\n" ); document.write( "S = surface area of the box
\n" ); document.write( "S = 2*(length*width + length*height + width*height)
\n" ); document.write( "480 = 2*(x*0.5x + x*(x+8) + 0.5x*(x+8))
\n" ); document.write( "480 = 2*(0.5x^2 + x^2+8x + 0.5x^2+4x)
\n" ); document.write( "480 = 2*(2x^2 +12x)
\n" ); document.write( "480 = 4x^2 +24x
\n" ); document.write( "4x^2+24x-480 = 0
\n" ); document.write( "4(x^2+6x-120) = 0
\n" ); document.write( "x^2+6x-120 = 0/4
\n" ); document.write( "x^2+6x-120 = 0\r
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\n" ); document.write( "\n" ); document.write( "Plug a = 1, b = 6, c = -120 into the quadratic formula.
\n" ); document.write( "\"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-6%2B-sqrt%28%286%29%5E2-4%281%29%28-120%29%29%29%2F%282%281%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-6%2B-sqrt%2836+%2B+480%29%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-6%2B-sqrt%28516%29%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-6%2B-sqrt%284%2A129%29%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-6%2B-sqrt%284%29%2Asqrt%28129%29%29%2F%282%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-6%2B-+2%2Asqrt%28129%29%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282%28-3%2B-sqrt%28129%29%29%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-3%2B-sqrt%28129%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+-3%2Bsqrt%28129%29\" or \"x+=+-3-sqrt%28129%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+8.357816691601\" or \"x+=+-14.357816691601\"
\n" ); document.write( "Ignore the negative x value.
\n" ); document.write( "A negative length makes no sense.
\n" ); document.write( "Each decimal value mentioned is approximate.
\n" ); document.write( "Round it however your teacher instructs.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Add 8 to the length to find the height.
\n" ); document.write( "\"height+=+x%2B8+=+-3%2Bsqrt%28129%29%2B8+=+5%2Bsqrt%28129%29+=+16.357816691601\"
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