document.write( "Question 1209105: My street hockey team plays three games each week. My team lost all $9$ games in the first three weeks. Then, my team won one game and lost two games in the fourth week, bringing our record to $1$ win and $11$ losses. Each week after that, my team won one game and lost two games. My team first wins at least $60\%$ of all its games by the end of the first $n$ weeks. What is $n$? \n" ); document.write( "
Algebra.Com's Answer #847687 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "first three weeks: won 0 games out of 9 games total
\n" ); document.write( "through 4 weeks: won 1 game out of 12 games total
\n" ); document.write( "through 5 weeks: won 2 games out of 15 games total
\n" ); document.write( "through 6 weeks: won 3 games out of 18 games total
\n" ); document.write( "...etc...
\n" ); document.write( "through n weeks: won n-3 games out of 3n games total\r
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\n" ); document.write( "\n" ); document.write( "Divide the win count over the total, and multiply by 100, to get the win percentage
\n" ); document.write( "For instance if you won A = 3 games out of B = 18 total then winPercentage = (100%)*A/B = (100%)*3/18 = 16.67% approximately\r
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\n" ); document.write( "\n" ); document.write( "This means 100*(n-3)/(3n) represents the win percentage through the nth week.\r
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\n" ); document.write( "\n" ); document.write( "As n gets bigger and bigger, the win percentage will slowly approach 100*n/(3n) = 100*(1/3) = 33.3% approximately. It will never reach this value since this is an asymptote.
\n" ); document.write( "So the upper bound is that you'll win a third of your games if you play out to infinity and this pattern of \"1 win, 2 losses\" continues.
\n" ); document.write( "This should be fairly obvious because for any given week you win 1 game out of 3 total.
\n" ); document.write( "It's not possible to win 60% of your games no matter how large n gets.
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