document.write( "Question 1209057: ABC is an equilateral triangle. DE and DF are perpendiculars drawn from D to the sides shown. DE=4 cm and DF = 26 cm. Find the length, in cm, of the altitude AG.
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Algebra.Com's Answer #847674 by MathTherapy(10551)\"\" \"About 
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document.write( "ABC is an equilateral triangle. DE and DF are perpendiculars drawn from D to the sides shown. DE=4 cm and DF = 26 cm. \r\n" );
document.write( "Find the length, in cm, of the altitude AG.\r\n" );
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document.write( "As ΔABC is equilateral, ∡B = ∡C = 60o\r\n" );
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document.write( "From right ΔBED, hypotenuse BD = \"%282%2F3%29+%2A+matrix%281%2C2%2C+LONGER%2C+LEG%29+%2A+sqrt%283%29\"\r\n" );
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document.write( "From right ΔCFD, hypotenuse DC = \"%282%2F3%29+%2A+matrix%281%2C2%2C+LONGER%2C+LEG%29+%2A+sqrt%283%29\"\r\n" );
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document.write( "So, one side of equilateral triangle ABC, BC = BD + DC = \r\n" );
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document.write( "AC is also \"highlight%28highlight%2820sqrt%283%29%29%29\"\r\n" );
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document.write( "As an altitude from ANY vertex of ANY equilateral triangle, BISECTS that vertex' opposite side, altitude AG\r\n" );
document.write( "BISECTS BC, and therefore, BG = GC = \"%281%2F2%29BC\" = \r\n" );
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document.write( "Since AC = \"20sqrt%283%29\", and GC = \"10sqrt%283%29\", we use the PYTHAGOREAN THEOREM formula to get: \r\n" );
document.write( "                                                                                       30 cm = AG
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