document.write( "Question 1209097: Line \ell_1 represents the graph of 3x + 2y = -14. Line \ell_2 passes through the point (0,0), and is perpendicular to line \ell_1. Write the equation of line \ell_2 in the form y=mx +b. \n" ); document.write( "

Algebra.Com's Answer #847673 by ikleyn(52754) $\"\"$ $\"About$

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document.write( "The commonly known fact is that if you have a line\r\n" );
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document.write( "    ax + by = c,\r\n" );
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document.write( "then a perpendicular line is\r\n" );
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document.write( "    -bx + ay = d   (where \"a\", \"b\", \"c\" and \"d\" are constant values).\r\n" );
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document.write( "Using it, we see that in our case an equation of the desired line is\r\n" );
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document.write( "    -2x + 3y = d    (where d is some constant).\r\n" );
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document.write( "And since this line should pass through (0,0),  d = 0.\r\n" );
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document.write( "Thus, the desired equation is\r\n" );
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document.write( "    3y = 2x,\r\n" );
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document.write( "or, in the form y = ax+b, it is\r\n" );
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document.write( "    y = .    ANSWER\r\n" );
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