document.write( "Question 1209088: There are two equilateral triangles with different areas, where O and O' are their circumcenters respectively. In the first, the distance OA is 9 cm, and in the second, the distance O'C' is 4√2 cm. Find the ratio of the area of the first to the area of the second.
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Algebra.Com's Answer #847666 by ikleyn(52873)\"\" \"About 
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\n" ); document.write( "There are two equilateral triangles with different areas, where O and O' are t
\n" ); document.write( "heir circumcenters respectively. In the first, the distance OA is 9 cm,
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document.write( "These equilateral triangles are similar (as any two equilateral triangles,\r\n" );
document.write( "by three angles). \r\n" );
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document.write( "Their corresponding similar elements are OC and O'C'.\r\n" );
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document.write( "In the second triangle, we are given  O'C' = \"4%2Asqrt%282%29\" cm.\r\n" );
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document.write( "In the first triangle, we are given OA = 9 cm.\r\n" );
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document.write( "      But triangle OAC is a right-angled 90°-60°-30°-triangle;\r\n" );
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document.write( "      therefore, the hypotenuse OC is twice the leg OA,\r\n" );
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document.write( "      so, the hypotenuse OC is 2*9 = 18 cm.\r\n" );
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document.write( "Thus, the ratio of corresponding linear dimensions in triangles is\r\n" );
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document.write( "    OC        18            9         9*sqrt(2)\r\n" );
document.write( "   ----- = ----------- = -------- = ----------.\r\n" );
document.write( "    O'C'    4*sqrt(2)     2*sqrt(2)      4\r\n" );
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document.write( "The ratio of the areas of the second triangle to the first triangle is the square\r\n" );
document.write( "of the ratio of their corresponding linear elements, i.e.\r\n" );
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document.write( "    \"%28%289%2Asqrt%282%29%29%2F4%29%5E2\" = \"%2881%2A2%29%2F16\" = \"81%2F8\" = 10.125.    ANSWER\r\n" );
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