document.write( "Question 1209045: If I give my brother $5$ dollars, then we will have the same amount of money. If instead he gives me $12$ dollars, then I'll have four times as much money as he will have. How much money does my brother currently have (in dollars)? \n" ); document.write( "

Algebra.Com's Answer #847617 by math_tutor2020(3816) $\"\"$ $\"About$

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\n" ); document.write( "Answer: $23.33\r
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\n" ); document.write( "\n" ); document.write( "Explanation\r
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\n" ); document.write( "\n" ); document.write( "x = amount of money you start with
\n" ); document.write( "y = amount of money your brother starts with\r
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\n" ); document.write( "\n" ); document.write( "Scenarion 1) You give your brother $5
\n" ); document.write( "Scenarion 2) Your brother gives you $12
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	Your amount	Your brother's amount
Scenario 1	x-5	y+5
Scenario 2	x+12	y-12

\n" ); document.write( "At the conclusion of scenario 1, the two of you have the same amount of money.
\n" ); document.write( "your amount = his amount
\n" ); document.write( "x-5 = y+5
\n" ); document.write( "y = x-5-5
\n" ); document.write( "y = x-10
\n" ); document.write( "We'll use this equation later in a substitution step.\r
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\n" ); document.write( "\n" ); document.write( "At the conclusion of scenario 2, you have four times as much money compared to your brother.
\n" ); document.write( "your amount = 4*(his amount)
\n" ); document.write( "x+12 = 4*(y-12)
\n" ); document.write( "x+12 = 4*(y-12)
\n" ); document.write( "x+12 = 4*(x-10-12) .... substitution
\n" ); document.write( "x+12 = 4(x-22)
\n" ); document.write( "x+12 = 4x-88
\n" ); document.write( "x-4x = -88-12
\n" ); document.write( "-3x = -100
\n" ); document.write( "x = -100/(-3)
\n" ); document.write( "x = 100/3
\n" ); document.write( "x = 33.33 dollars approximately
\n" ); document.write( "y = x-10 = 33.33 - 10 = 23.33 dollars is the amount your brother starts with.\r
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\n" ); document.write( "\n" ); document.write( "Check:
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	Your amount	Your brother's amount
Scenario 1	33.33-5 = 28.33	23.33+5 = 28.33
Scenario 2	33.33+12 = 45.33	23.33-12 = 11.33

\n" ); document.write( "45.33/11.33 = 4.000882612533 approximately
\n" ); document.write( "We don't land on 4 exactly, but we get close enough.
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