document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1209001>Question 1209001</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that you have entered an 87-mile biathlon that consists of a run and a bicycle race. During your run, your average speed is 6 miles per hour, and during your bicycle race, your average speed is 25 miles per hour. You finish the race in 5 hours. What is the distance of the run? What is the distance of the bicycle race? </SPAN>\n" );
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document.write( "Here is a VERY different approach to solving the problem than the standard algebraic method shown by the other tutors.<br><BR>\n" );
document.write( "Your average speed running is 6 mph; your average speed cycling is 25 mph.<br><BR>\n" );
document.write( "Your overall average speed is 87/5 = 17.4 mph.<br><BR>\n" );
document.write( "Use a number line if it helps to observe/calculate that 17.4 is 3/5 of the way from 6 to 25.  That means 3/5 of the total time was at the higher speed.<br><BR>\n" );
document.write( "The total time was 5 hours, and 3/5 of the time, or 3 hours, was at the higher speed.<br><BR>\n" );
document.write( "So your cycling time was 3 hours and your running time was 2 hours.<br><BR>\n" );
document.write( "The cycling distance, 3 hours at 25 mph, was 3*25 = 75 miles.<br><BR>\n" );
document.write( "The running distance, 2 hours at 6 mph, was 2*6 = 12 miles.<br><BR>\n" );
document.write( "ANSWERS:<BR>\n" );
document.write( "running distance: 12 miles<BR>\n" );
document.write( "cycling distance: 75 miles<br><BR>\n" );
document.write( " </SPAN>\n" );
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