document.write( "Question 1209001: Suppose that you have entered an 87-mile biathlon that consists of a run and a bicycle race. During your run, your average speed is 6 miles per hour, and during your bicycle race, your average speed is 25 miles per hour. You finish the race in 5 hours. What is the distance of the run? What is the distance of the bicycle race? \n" ); document.write( "

Algebra.Com's Answer #847576 by ikleyn(52790) $\"\"$ $\"About$

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\n" ); document.write( "Suppose that you have entered an 87-mile biathlon that consists of a run and a bicycle race.
\n" ); document.write( "During your run, your average speed is 6 miles per hour, and during your bicycle race,
\n" ); document.write( "your average speed is 25 miles per hour. You finish the race in 5 hours.
\n" ); document.write( "What is the distance of the run? What is the distance of the bicycle race?
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document.write( "Let \"t\" be the time running, in hours.\r\n" );
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document.write( "Then the time cycling is (5-t) hours.\r\n" );
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document.write( "The total distance equation is \r\n" );
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document.write( "    6t + 25(5-t) = 87  miles.\r\n" );
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document.write( "Simplify and find \"t\"\r\n" );
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document.write( "    6t + 125 - 25t = 87,\r\n" );
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document.write( "     125 - 87 = 25t - 6t\r\n" );
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document.write( "         38   =    19t\r\n" );
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document.write( "          t    =    38/19 = 2 hours.\r\n" );
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document.write( "So, you run 2 hours and cycle 5-2 = 3 hours.\r\n" );
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document.write( "The distance running is  6*2 = 12 miles.  The distance cycling is 25*3 = 75 miles.    ANSWER\r\n" );
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