document.write( "Question 1208988:
\n" ); document.write( "An air rescue plane averages 300 miles per hour in still air. It carries enough fuel for 5 hours of flying time. If, upon takeoff, it encounters a head wind of 30 mi/hr, how far can it fly and return safely? (Assume that the wind remains constant.)\r
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Algebra.Com's Answer #847536 by ikleyn(52786) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "An air rescue plane averages 300 miles per hour in still air.
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\n" ); document.write( "If, upon takeoff, it encounters a head wind of 30 mi/hr, how far can it fly
\n" ); document.write( "and return safely? (Assume that the wind remains constant.)
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document.write( "Let d be the maximum one way distance, in miles.\r\n" );
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document.write( "The rate of the plane (relative the ground) against the wind is 300-30 = 270 mils per hour.\r\n" );
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document.write( "The time to fly the distance of d miles is   hours.\r\n" );
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document.write( "The rate of the plane (relative the ground) with the wind is 300+30 = 330 mils per hour.\r\n" );
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document.write( "The time to fly the distance of d miles is   hours.\r\n" );
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document.write( "The total time flying is   + .\r\n" );
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document.write( "The time equation is\r\n" );
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document.write( "     +  = 5  hours.\r\n" );
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document.write( "To solve, multiply all the terms by  270*330.  You will get\r\n" );
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document.write( "    330d + 270d = 5*270*330\r\n" );
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document.write( "    600d = 445500\r\n" );
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document.write( "       d = 445500/600 = 742.5.\r\n" );
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document.write( "ANSWER.  The maximum one-way distance to fly is  742.5 miles.\r\n" );
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