document.write( "Question 1208980: In the diagram AD = 4 cm, EF = 3 cm, and parallel segments are indicated. If the total area of the trapezoid is 135 cm2, what is the area, in cm2, of triangle AMN?
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Algebra.Com's Answer #847535 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I'll recreate the diagram just in case the link might expire (at some point in the future). \n" ); document.write( " \n" ); document.write( "Note that I'm copying the arrow style (to the best of my ability) shown in the diagram link. Your teacher/textbook should use different arrow styles for a different set of parallel segments. For instance AB & ED could have single arrow, while AF & DC have double arrows.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The arrows on the segments tell us the following \n" ); document.write( "AB is parallel to DE \n" ); document.write( "BC is parallel to AD \n" ); document.write( "AF is parallel to DC\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Consequently it means ADEB and ADCF are parallelograms. \n" ); document.write( "The opposite sides of a parallelogram are congruent, which leads to AD = BE = 4 and AD = FC = 4. \n" ); document.write( "BC = BE+EF+FC = 4+3+4 = 11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "h = height of trapezoid ABCD \n" ); document.write( "area of trapezoid = 0.5*height*(base1+base2) \n" ); document.write( "area of trapezoid ABCD = 0.5*h*(AD+BC) \n" ); document.write( "135 = 0.5*h*(AD+BC) \n" ); document.write( "0.5*h*(4+11) = 135 \n" ); document.write( "7.5h = 135 \n" ); document.write( "h = 135/7.5 \n" ); document.write( "h = 18 \n" ); document.write( "Trapezoid ABCD has height 18 cm. \n" ); document.write( "This is also the height of triangle ABF when working with base BF.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Focus on triangle ABF. \n" ); document.write( "To avoid clutter, you can create a quick sketch of triangle ABF off to the side somewhere. \n" ); document.write( "area = 0.5*base*height \n" ); document.write( "area = 0.5*BF*h \n" ); document.write( "area = 0.5*(BE+EF)*h \n" ); document.write( "area = 0.5*(4+3)*18 \n" ); document.write( "area = 63 square cm\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notice that triangles ABF and NEF are similar triangles (use the Angle Angle Theorem; I will leave this as an exercise for the student).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's compare the horizontal portions of each triangle. \n" ); document.write( "The ratio of segment EF to BF is 3:7 \n" ); document.write( "Square both parts to get 9:49 which is the ratio of their areas. \n" ); document.write( "This new ratio means that if triangle NEF had area 9 square cm, then triangle ABF would have an area of 49 square cm.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In other words, triangle NEF takes up 9/49 of triangle ABF's area. \n" ); document.write( "The remaining portion is 1 - (9/49) = 40/49 which is what trapezoid ANEB takes up.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "area of ANEB = (40/49)*(area of triangle ABF) \n" ); document.write( "= (40/49)*(63) \n" ); document.write( "= (360/7) square cm \n" ); document.write( "= 51.42857 square cm approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now focus on triangle ABC. \n" ); document.write( "area = 0.5*base*height \n" ); document.write( "area = 0.5*BC*h \n" ); document.write( "area = 0.5*11*18 \n" ); document.write( "area = 99 square cm\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Triangles MEC and ABC are similar. \n" ); document.write( "The ratio of the horizontal pieces EC to BC is 7:11 \n" ); document.write( "Both parts square to 49:121 which is the ratio of the areas MEC to ABC. \n" ); document.write( "Triangle MEC takes up 49/121 of triangle ABC. \n" ); document.write( "Trapezoid AMEB takes up 1 - (49/121) = 72/121 of triangle ABC's area.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "area of AMEB = (72/121)*(area of triangle ABC) \n" ); document.write( "= (72/121)*(99) \n" ); document.write( "= (648/11) square cm \n" ); document.write( "= 58.90909 square cm approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are a lot of things to keep track of. \n" ); document.write( "But the two key important things are: \n" ); document.write( "area of trapezoid AMEB = (648/11) square cm \n" ); document.write( "area of trapezoid ANEB = (360/7) square cm\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtracting those areas will get us the area of triangle AMN. \n" ); document.write( "area AMN = (area AMEB) - (area ANEB) \n" ); document.write( "area AMN = (648/11) - (360/7) \n" ); document.write( "area AMN = (648/11)*(7/7) - (360/7)*(11/11) \n" ); document.write( "area AMN = (648*7)/(11*7) - (360*11)/(7*11) \n" ); document.write( "area AMN = 4536/77 - 3960/77 \n" ); document.write( "area AMN = (4536 - 3960)/77 \n" ); document.write( "area AMN = (576/77) square cm exactly \n" ); document.write( "area AMN = 7.480519480519 square cm approximately \n" ); document.write( "Round this approximate value however needed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I have confirmed this answer is correct using GeoGebra \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A similar problem is found here \n" ); document.write( " \n" ); document.write( " |