document.write( "Question 1208984: ABC is an equilateral triangle with sides of length 8 cm. Arc- AB, Arc-AC and Arc- BC are arcs of circles having their centres at C, B and A respectively. Find the total area of the non-shaded region of the diagram, in cm2.
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Algebra.Com's Answer #847531 by ikleyn(52814)\"\" \"About 
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\n" ); document.write( "ABC is an equilateral triangle with sides of length 8 cm. Arc- AB, Arc-AC and Arc- BC are arcs
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document.write( "The non-shaded area consists of three disjoint congruent shapes.\r\n" );
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document.write( "For each shape, its area is 1/6 of the area of the circle with the radius of 8 cm\r\n" );
document.write( "minus the area of the equilateral triangle with the side of 8 cm.\r\n" );
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document.write( "So, the non-shaded area is  \r\n" );
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document.write( "      \"3%2A%281%2F6%29%2Api%2A8%5E2+-+3%2A8%5E2%2A%28sqrt%283%29%2F4%29\" =  \"%281%2F2%29%2A64%2Api+-+3%2A64%2A%28sqrt%283%29%2F4%29\" = \"32%2Api-3%2A16%2Asqrt%283%29\" = \r\n" );
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document.write( "    = \"32%2A3.14159-48%2Asqrt%283%29\" = 17.39244  cm^2  (rounded).    ANSWER\r\n" );
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