document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1208965>Question 1208965</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 7 more that 3 times its width. if the perimeter is 38 cm, what is the area, in square centimeters, of the rectangle <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #847506 by </B><A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><B>math_tutor2020(3816)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=847506\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=black size=3><BR>\n" );
document.write( "w = width<BR>\n" );
document.write( "3w = three times the width<BR>\n" );
document.write( "3w+7 = seven more than the previous amount = length\r<BR>\n" );
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document.write( "perimeter = 2*(length+width)<BR>\n" );
document.write( "perimeter = 2*(3w+7 + w)<BR>\n" );
document.write( "2*(4w+7) = 38<BR>\n" );
document.write( "8w+14 = 38<BR>\n" );
document.write( "8w = 38-14<BR>\n" );
document.write( "8w = 24<BR>\n" );
document.write( "w = 24/8<BR>\n" );
document.write( "w = 3 cm is the width<BR>\n" );
document.write( "length = 3w+7 = 3*3+7 = 16 cm\r<BR>\n" );
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document.write( "area = length*width = 16*3 = <font color=red>48 square centimeters</font><BR>\n" );
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