document.write( "Question 1208954: not sure how to prove this?\r
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\n" ); document.write( "\n" ); document.write( "if n is odd then n^2 = 1 (mod 4)\r
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Algebra.Com's Answer #847497 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "not sure how to prove this?\r
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\n" ); document.write( "\n" ); document.write( "if n is odd then n^2 = 1 (mod 4)\r
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\n" ); document.write( "\n" ); document.write( "                It is easy.\r
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document.write( "If n is odd integer number, it can be presented in the form  n = 2k+1,  \r\n" );
document.write( "where k is some integer number.\r\n" );
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document.write( "Then \r\n" );
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document.write( "    n^2 = (2k)^2 + 2*(2k) + 1 = 4k^2 + 4k + 1.    (1)\r\n" );
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document.write( "In the right side, first addend, 4k^2, is a multiple of 4, \r\n" );
document.write( "and the second addend 4k is a multiple of k.\r\n" );
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document.write( "Hence, the sum of the first two addends is a multiple of k.\r\n" );
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document.write( "Thus n^2 = 1 (mod 4).\r\n" );
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\n" ); document.write( "\n" ); document.write( "At this point, the proof is complete.\r
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\n" ); document.write( "\n" ); document.write( "In whole, this all is at the level of self-evident truths.\r
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