document.write( "Question 1208936: True or false? The sum of rational and irrational number is rational \n" ); document.write( "
Algebra.Com's Answer #847469 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: False\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation \n" ); document.write( "x = rational number \n" ); document.write( "y = irrational number \n" ); document.write( "x = a/b for some integers a,b where b is nonzero \n" ); document.write( "y cannot be written as a fraction of integers because it is set up to be irrational.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Assume x+y was rational. \n" ); document.write( "We'll do a proof by contradiction to show that x+y is instead irrational. \n" ); document.write( "x+y = rational \n" ); document.write( "x+y = p/q \n" ); document.write( "(a/b) + y = p/q \n" ); document.write( "y = (p/q) - (a/b) \n" ); document.write( "y = (bp)/(bq) - (aq)/(bq) \n" ); document.write( "y = (bp-aq)/(bq) \n" ); document.write( "y = (some integer)/(some integer) \n" ); document.write( "y = rational number \n" ); document.write( "But wait, we made y irrational and now it's rational. \n" ); document.write( "This is clearly a contradiction.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "A number cannot be both rational and irrational at the same time. \n" ); document.write( "The term \"irrational\" literally means \"not rational\". \n" ); document.write( "This contradiction means the assumption x+y = rational is false, so x+y = irrational must be the case.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A template to write down in your notes would be rational + irrational = irrational \n" ); document.write( " \n" ); document.write( " |