document.write( "Question 1208896: If 0 < a < b, show that a < sqrt{ab} < b. \r
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Algebra.Com's Answer #847411 by Edwin McCravy(20060) $\"\"$ $\"About$

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document.write( "0 < a < b\r\n" );
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document.write( "Multiply through by a:\r\n" );
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document.write( "Nonnegative square roots are in the same order of inequality as their squares. \r\n" );
document.write( "So we take nonnegative square roots:\r\n" );
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document.write( "0 < a < b\r\n" );
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document.write( "Multiply through by b:\r\n" );
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document.write( "Nonnegative square roots are in the same order of inequality as their squares. \r\n" );
document.write( "So we take nonnegative square roots:\r\n" );
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document.write( " and \r\n" );
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document.write( "Therefore \r\n" );
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document.write( "Edwin

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