Algebra.Com's Answer #847386 by ikleyn(52787)  You can put this solution on YOUR website! . \n" );
document.write( "A man calculates that if he continues at the present speed, to drive the remaining 100km \n" );
document.write( "of his trip, he will arrive 30 minutes late. In order to arrive on time, he must travel \n" );
document.write( "at an average rate of 10 kph faster. What is his present speed? \n" );
document.write( "~~~~~~~~~~~~~~~~~~\r \n" );
document.write( " \n" );
document.write( "\n" );
document.write( "\r\n" );
document.write( "Let v be the man's present speed, in kilometers per hour.\r\n" );
document.write( "\r\n" );
document.write( "Then the other, hypothetical speed is (v+10) km/h.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The time to drive 100 km at the speed v km/h is hours.\r\n" );
document.write( "\r\n" );
document.write( "The time to drive 100 km at the speed (v+10) km/h is hours.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The problem says that time is 30 minutes, or 1/2 of an hour less than time .\r\n" );
document.write( "\r\n" );
document.write( "So, we write this time equation\r\n" );
document.write( "\r\n" );
document.write( " - = of an hour.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "At this point, the setup is complete.\r\n" );
document.write( "To solve this equation, multiply its terms by 2v*(v+10) in both sides.\r\n" );
document.write( "You will get\r\n" );
document.write( "\r\n" );
document.write( " 100*2*(v+10) - 100*2*v = v*(v+10),\r\n" );
document.write( "\r\n" );
document.write( " 200v + 2000 - 200v = v^2 + 10v\r\n" );
document.write( "\r\n" );
document.write( " v^2 + 10v - 2000 = 0.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Factor left side\r\n" );
document.write( "\r\n" );
document.write( " (v+50)*(v-40) = 0.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "This equation has two roots, v= -50 and v= 40.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Since v should be positive, due to its meaning, we accept the positive root v= 40 km/h\r\n" );
document.write( "and deny the negative root.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "So, the ANSWER to the problem is that the present speed of driving is 40 km/h.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "CHECK. Driving time at the present speed is = 2 hours.\r\n" );
document.write( "\r\n" );
document.write( " Driving time at the speed of 40+10 = 50 km/h is = 2 hours.\r\n" );
document.write( "\r\n" );
document.write( " The difference of the two driving times is 1/2 of an hour, or precisely 30 minute,\r\n" );
document.write( "\r\n" );
document.write( " which confirms that the answer is correct.\r\n" );
document.write( " \r \n" );
document.write( "\n" );
document.write( "Solved completely.\r \n" );
document.write( " \n" );
document.write( " \n" );
document.write( "\n" );
document.write( "This solution method (using time equation) is a standard approach for solving similar problems.\r \n" );
document.write( " \n" );
document.write( " \n" );
document.write( "\n" );
document.write( " \n" );
document.write( " |