document.write( "Question 1208852: A civil engineer relates the thickness T, in inches, and height H, in feet, of a square wooden pillar to its crushing load L, in tons, using the model T = [{(LH^2)/25}]^(1/4). If a square wooden pillar is 4 inches thick and 10 feet high, what is its crushing load? \n" ); document.write( "
Algebra.Com's Answer #847340 by ikleyn(52778)\"\" \"About 
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document.write( "The units in the formula and the units of the given values coincide.\r\n" );
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document.write( "So, you can directly substitute the given values into the formula\r\n" );
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document.write( "    the crushing load L = \"%28LH%5E2%29%2F25%29%5E%281%2F4%29\" = \"%28%284%2A10%5E2%29%2F25%29%5E%281%2F4%29\" = \"%28400%2F25%29%5E%281%2F4%29\" = 16^(1/4) = 2 tons.    ANSWER\r\n" );
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