document.write( "Question 116536: Solve the equation by completing the square.
\n" ); document.write( " $\"x%5E2\"$ +12x=-13 \n" ); document.write( "

Algebra.Com's Answer #84724 by jgr45(31) $\"\"$ $\"About$

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$\"x%5E2\"$ +12x = -13\r
\n" ); document.write( "\n" ); document.write( "To complete the square, you take half of the x-coefficient and square it to find the third term. Here 12 halved is 6, the square of which is 36. So that's the constant. Adding 36 to both sides we get:\r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2\"$ +12x+36 = 23
\n" ); document.write( " $\"%28x%2B6%29%5E2\"$ = 23
\n" ); document.write( "x+6 = $\"sqrt%2823%29\"$ \r
\n" ); document.write( "\n" ); document.write( "x = + - $\"sqrt%2823%29\"$ - 6
\n" ); document.write( " \n" ); document.write( "

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