document.write( "Question 1208761: Dear Genii
\n" ); document.write( "I have what I fear is a rather silly question. The other day I came across this question on a GCSE maths paper:
\n" ); document.write( "x-y = k
\n" ); document.write( "x^2+y^2-9=0\r
\n" ); document.write( "\n" ); document.write( "These simultaneous equations have exactly one set of solutions.
\n" ); document.write( "Show that k = +/_3root2 (I don't know hoe to put the square root sign in.\r
\n" ); document.write( "\n" ); document.write( "I have never come across questions like this before and I have no idea what this method/technique is called; I have no idea why it is used and I have no idea about how to solve such questions. I would very much appreciate it if someone could tell me what this technique is called, why it is used and where I might find instructions about how to use it.\r
\n" ); document.write( "\n" ); document.write( "Marcus Clayson
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Algebra.Com's Answer #847194 by math_tutor2020(3816)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "sqrt is shorthand for \"square root\"
\n" ); document.write( "example: sqrt(5) = \"sqrt%285%29\"\r
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\n" ); document.write( "\n" ); document.write( "x-y = k solves to y = x-k\r
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\n" ); document.write( "\n" ); document.write( "Plug this into the other equation to see what happens.
\n" ); document.write( "x^2 + y^2 - 9 = 0
\n" ); document.write( "x^2 + (y)^2 - 9 = 0
\n" ); document.write( "x^2 + (x-k)^2 - 9 = 0
\n" ); document.write( "x^2 + x^2 - 2kx + k^2 - 9 = 0
\n" ); document.write( "2x^2 - 2kx + k^2 - 9 = 0\r
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\n" ); document.write( "\n" ); document.write( "In terms of the variable x we have this quadratic template.
\n" ); document.write( "ax^2 + bx + c = 0
\n" ); document.write( "where in this case,
\n" ); document.write( "a = 2
\n" ); document.write( "b = -2k
\n" ); document.write( "c = k^2 - 9\r
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\n" ); document.write( "\n" ); document.write( "If the original system has one solution for a fixed specific value of k, then the equation 2x^2 - 2kx + k^2 - 9 = 0 must have one solution.
\n" ); document.write( "A quadratic having one solution would only happen when the discriminant is equal to 0.
\n" ); document.write( "d = b^2 - 4ac = discriminant\r
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\n" ); document.write( "\n" ); document.write( "b^2 - 4ac = 0
\n" ); document.write( "(-2k)^2 - 4(2)(k^2-9) = 0 .......... plug in the a,b,c values mentioned earlier
\n" ); document.write( "4k^2 - 8(k^2-9) = 0
\n" ); document.write( "4k^2 - 8k^2 + 72 = 0
\n" ); document.write( "-4k^2 + 72 = 0
\n" ); document.write( "4k^2 - 72 = 0
\n" ); document.write( "4k^2 = 72
\n" ); document.write( "k^2 = 72/4
\n" ); document.write( "k^2 = 18
\n" ); document.write( "k = plus minus sqrt(18)
\n" ); document.write( "k = sqrt(18) or k = -sqrt(18)
\n" ); document.write( "k = sqrt(9*2) or k = -sqrt(9*2)
\n" ); document.write( "k = sqrt(9)*sqrt(2) or k = -sqrt(9)*sqrt(2)
\n" ); document.write( "k = 3*sqrt(2) or k = -3*sqrt(2)\r
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\n" ); document.write( "\n" ); document.write( "Below is a graph of when k = 3*sqrt(2)
\n" ); document.write( "This makes the line x-y = k tangent to the circle toward the bottom right portion of the circle.
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\n" ); document.write( "The circle is centered at (0,0) and has radius 3.
\n" ); document.write( "GeoGebra and Desmos are two of many graphing tools I recommend to use.\r
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\n" ); document.write( "\n" ); document.write( "And here is the graph when k = -3*sqrt(2)
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\n" ); document.write( "We have another situation where the line is tangent to the circle.
\n" ); document.write( "That tangent point is the solution to the system.\r
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\n" ); document.write( "\n" ); document.write( "If -3*sqrt(2) < k < 3*sqrt(2), then the line x-y = k intersects the circle at two different locations. \r
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\n" ); document.write( "\n" ); document.write( "If k < -3*sqrt(2) or k > 3*sqrt(2), then the line doesn't intersect the circle at all and there are no solutions. \r
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\n" ); document.write( "\n" ); document.write( "Here is an interactive Desmos graph to try out
\n" ); document.write( "https://www.desmos.com/calculator/zijda3qbgr
\n" ); document.write( "Move the slider for parameter k so you can see how the blue line moves around. \r
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\n" ); document.write( "\n" ); document.write( "3*sqrt(2) = 4.24264 approximately
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