document.write( "Question 1079215: 5 men are hired to complete a job. If one more man is hired, the job can be completed 8 days earlier. Assuming that all the men work at the same rate, how many more men should be hired so that the job can be completed 28 days earlier? \n" ); document.write( "
Algebra.Com's Answer #847178 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "We have two scenarios for completing the job:
\n" ); document.write( "(1) 5 men working for x days; and
\n" ); document.write( "(2) 6 men working for (x-8) days

\n" ); document.write( "In the first scenario, the job requires 5(x) man-days; in the second, it requires 6(x-8) days. Those amounts of time required to complete the job are the same:

\n" ); document.write( "5x=6(x-8)
\n" ); document.write( "5x=6x-48
\n" ); document.write( "x=48

\n" ); document.write( "It takes 5 men 48 days to do the job, so the number of man-days required to complete the job is 5(48) = 240.

\n" ); document.write( "The third scenario has the job being completed in 28 fewer days -- i.e., 48-28 = 20 days.

\n" ); document.write( "The job requires 240 man-days to complete; if it is to be completed in 20 days, the number of men needed is 240/20 = 12.

\n" ); document.write( "There are currently 5 men working on the job, so the number of additional men needed to complete the job 28 days earlier is 12-5 =7.

\n" ); document.write( "ANSWER: 7
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