document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1208745>Question 1208745</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Expand (x + 2)(3x^2 + 12) + (x - 2).<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #847176 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13206)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=847176\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "(x + 2)(3x^2 + 12) + (x - 2)<br><BR>\n" );
document.write( "In the first part of the expression, multiply each term of the first polynomial by each term of the second.<br><BR>\n" );
document.write( "x(3x^2) = 3x^3<BR>\n" );
document.write( "x(12) = 12x<BR>\n" );
document.write( "2(3x^2) = 6x^2<BR>\n" );
document.write( "2(12) = 24<br><BR>\n" );
document.write( "The product of the two polynomials is the sum of those partial products<br><BR>\n" );
document.write( "3x^3+6x^2+12x+24<br><BR>\n" );
document.write( "When adding the last part of the expression, combine like terms if there are any.<br><BR>\n" );
document.write( "(3x^3+6x^2+12x+24) + (x-2) = 3x^3+6x^2+(12+1)x+(24-2)<br><BR>\n" );
document.write( "ANSWER: 3x^3+6x^2+13x+22<br><BR>\n" );
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