document.write( "Question 1208736: The window of a house is 6m above ground. A rocket is set off from the ground at an initial velocity of 20m/s.
\n" ); document.write( "For how many seconds will the rocket be at or above the window?
\n" ); document.write( "Use the equation
\n" ); document.write( "S(T)= -4.9T^2 + VoT + So to model the position S for a given time T, where Vo is the initial Velocity.
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Algebra.Com's Answer #847154 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "V0 = initial velocity = 20 meters per second
\n" ); document.write( "s0 = initial height = 0 meters because it was launched on the ground\r
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\n" ); document.write( "\n" ); document.write( "S(t) = -4.9t^2 + V0t + s0
\n" ); document.write( "S(t) = -4.9t^2 + 20t + 0
\n" ); document.write( "S(t) = -4.9t^2 + 20t
\n" ); document.write( "y = -4.9x^2 + 20x\r
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\n" ); document.write( "\n" ); document.write( "Using a graphing tool like GeoGebra or Desmos (among many other options), you should get the following graph
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\n" ); document.write( "y = -4.9x^2+20x is the parabola
\n" ); document.write( "y = 6 is the horizontal line\r
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\n" ); document.write( "\n" ); document.write( "The parabola and horizontal line intersect at points A and B.
\n" ); document.write( "A = (0.326,6)
\n" ); document.write( "B = (3.756,6)
\n" ); document.write( "The decimal values are approximate. Round them however your teacher instructs.
\n" ); document.write( "Another way to find these decimal solutions is to use the quadratic formula to solve -4.9x^2 + 20x - 6 = 0.\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the rocket's height is at or above 6 meters on the interval \"0.326+%3C=+t+%3C=+3.756\"
\n" ); document.write( "This is the portion of the curve between A and B.
\n" ); document.write( "This duration is roughly 3.43 seconds because 3.756-0.326 = 3.43\r
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\n" ); document.write( "\n" ); document.write( "More practice is found here
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