document.write( "Question 1208673: The length of a rectangle is eight more than twice it's width. The perimeter is 88 feet. Find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #847066 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "The length of a rectangle is eight $\"highlight%28highlight%28feet%29%29\"$ more than twice ~~it's~~ $\"highlight%28highlight%28its%29%29\"$ width.
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document.write( "Let the width be w feet.\r\n" );
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document.write( "Then the length is 2w+8 feet.\r\n" );
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document.write( "    Length + width = 88/2\r\n" );
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document.write( "    Length + width = 44\r\n" );
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document.write( "    (2w+8) + w = 44\r\n" );
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document.write( "    3w + 8 = 44\r\n" );
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document.write( "    3w = 44 - 8 = 36\r\n" );
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document.write( "     w = 36/3 = 12.\r\n" );
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document.write( "ANSWER.  The width is 12 feet;  the length is 2w+8 = 2*12+8 = 32 feet.\r\n" );
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document.write( "CHECK.  Length + width = 32 + 12 = 44 feet, one half of 88 feet, the perimeter.    ! correct !\r\n" );
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