document.write( "Question 1208661: Solve for b.\r
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Algebra.Com's Answer #847049 by ikleyn(52787)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "You start from\r\n" );
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document.write( "    \"%28x%2Fa%29\" + \"%28x%2Fb%29%5E2\" = c.\r\n" );
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document.write( "    As your starting equation is written in this form, \r\n" );
document.write( "    it is assumed implicitly that a =/=0,  b =/= 0.\r\n" );
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document.write( "Isolate the term with b in the left side\r\n" );
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document.write( "    \"%28x%2Fb%29%5E2\" = c - \"x%2Fa\".\r\n" );
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document.write( "Since left side is the fraction, write right side as a fraction, too\r\n" );
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document.write( "    \"%28x%2Fb%29%5E2\" = \"%28ac+-+x%29%2Fa\".\r\n" );
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document.write( "It is the same as \r\n" );
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document.write( "    \"x%5E2%2Fb%5E2\" = \"%28ac-x%29%2Fa\".\r\n" );
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document.write( "Since  \"b%5E2\"  is now in the denominator, turn both fractions upside down\r\n" );
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document.write( "    \"b%5E2%2Fx%5E2\" = \"a%2F%28ac-x%29\".\r\n" );
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document.write( "Multiply both sides by  \"x%5E2\"\r\n" );
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document.write( "    \"b%5E2\" = \"%28ax%5E2%29%2F%28ac-x%29\".\r\n" );
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document.write( "Now take square roots of both sides\r\n" );
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document.write( "    b = +/- \"sqrt%28%28ax%5E2%29%2F%28ac-x%29%29\" = +/- \"abs%28x%29%2Asqrt%28a%2F%28ac-x%29%29\".\r\n" );
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document.write( "Any of these two final expressions is the desired expression for b.\r\n" );
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document.write( "This final expression is valid under assumption that  ac-x =/= 0 and the expression under the square root is positive.\r\n" );
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