document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1208657>Question 1208657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the supplement of an angle is four times the complement of the angle find the measure of half the supplement of the angle<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #847043 by </B><A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><B>math_tutor2020(3817)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=847043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=black size=3><BR>\n" );
document.write( "x = the unknown angle<BR>\n" );
document.write( "180-x = the supplement of this angle<BR>\n" );
document.write( "90-x = the complement of the original angle<BR>\n" );
document.write( "Supplementary angles add to 180 degrees.<BR>\n" );
document.write( "Complementary angles add to 90 degrees.\r<BR>\n" );
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document.write( "The instructions mention that the supplement is 4 times the complement, <BR>\n" );
document.write( "supplement = 4*complement<BR>\n" );
document.write( "180-x = 4*(90-x)<BR>\n" );
document.write( "180-x = 360-4x<BR>\n" );
document.write( "-x+4x = 360-180<BR>\n" );
document.write( "3x = 180<BR>\n" );
document.write( "x = 180/3<BR>\n" );
document.write( "x = 60 is the original angle<BR>\n" );
document.write( "180-x = 180-60 = 120 is the supplement, which cuts in half to <font color=red>60 degrees</font>, so that is the final answer.<BR>\n" );
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