Algebra.Com's Answer #847041 by ikleyn(52781)![\"\"](\"/images/stars/stars-13.gif\")  
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document.write( "Given that 10^(2x)=0.2 and log5=0.6990, find value of x
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document.write( "Notice that 0.2 = 1/5. Therefore, log(0.2) =  = log(1) - log(5) = 0 - 0.6990 = -0.6990.\r\n" );
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document.write( "Now, we are given \r\n" );
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document.write( "  = 0.2.\r\n" );
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document.write( "Take logarithm base 10 of both sides. You will get\r\n" );
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document.write( " 2x = log(0.2) = as we deduced above = -0.699.\r\n" );
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document.write( "Hence, x = -0.6990/2 = -0.3495. ANSWER\r\n" );
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document.write( "CHECK.  = 0.2000 (rounded), which confirms the solution.\r\n" );
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document.write( "Solved.\r
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