document.write( "Question 1208652: The final velocity v of an object in feet per second (noted aa ft/sec) after it slides down a frictionless inclined plane of height h feet is given by\r
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\n" ); document.write( "\n" ); document.write( "v = sqrt{64h + (v_0)^2}, where v_0 is the initial velocity (in ft/sec) of the object.\r
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\n" ); document.write( "\n" ); document.write( "A. Solve the given formula for h.\r
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\n" ); document.write( "\n" ); document.write( "B. What is the final velocity v of an object that slides down a frictionless inclined plane of height 4 feet? Assume that the initial velocity is 0.
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Algebra.Com's Answer #847038 by Shin123(626)\"\" \"About 
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a)
\n" ); document.write( "Since the h is hard to work with when it's inside a square root, we square both sides to get \"v%5E2=64h%2B%28v_0%29%5E2\". Subtracting \"%28v_0%29%5E2\" from both sides gives \"64h=v%5E2-%28v_0%29%5E2\". Finally, dividing both sides by 64 gives \"h=%28v%5E2-%28v_0%29%5E2%29%2F64\".
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\n" ); document.write( "Going back to the original formula, we see that we have to plug in \"h=4\" and \"v_0=0\" from the problem statement. Doing so gives \"v=sqrt%2864%2A4%2B0%5E2%29=sqrt%28256%29=16\", so the final velocity is 16 ft/sec.
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