document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1208653>Question 1208653</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The period T, in seconds, of a pendulum of length L, in feet, may be approximated using the formula \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "T = 2•pi•sqrt{L/32}\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "For part B, express your answer both as a square root and as a decimal.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "A. Solve the given formula for L.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "B. Find the period T of a pendulum whose length is 8 inches.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "For part B, 8 inches must be converted to feet before substituting into the given formula.\r<BR>\n" );
document.write( "\n" );
document.write( "You say?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #847036 by </B><A HREF=/tutors/aboutme.mpl?userid=Shin123><B>Shin123(626)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Shin123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Shin123><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=847036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a)<BR>\n" );
document.write( "Note that we want to isolate the term that has L. Dividing both sides by 2pi gives <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28L%2F32%29=T%2F%282pi%29 ALIGN=MIDDLE  ALT=\"sqrt%28L%2F32%29=T%2F%282pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Squaring both sides gives <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L%2F32=T%5E2%2F%284pi%5E2%29 ALIGN=MIDDLE  ALT=\"L%2F32=T%5E2%2F%284pi%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Finally, multiplying both sides by 32 gives <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L=8T%5E2%2Fpi%5E2 ALIGN=MIDDLE  ALT=\"L=8T%5E2%2Fpi%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "b)<BR>\n" );
document.write( "There are 12 inches in a foot, so 8 inches is equal to 8/12 feet, or 2/3 feet. Plugging that in for L gives <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T=2pi%2Asqrt%28%282%2F3%29%2F32%29=2pi%2Asqrt%281%2F48%29=pi%2Fsqrt%2812%29 ALIGN=MIDDLE  ALT=\"T=2pi%2Asqrt%28%282%2F3%29%2F32%29=2pi%2Asqrt%281%2F48%29=pi%2Fsqrt%2812%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Simplifying and rationalizing gives <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T=pi%2Asqrt%283%29%2F6 ALIGN=MIDDLE  ALT=\"T=pi%2Asqrt%283%29%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Expressing this as a decimal gives 0.906899682... The answer is irrational, and so round it as necessary. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );