document.write( "Question 1208637: Hello! I would appreciate it if you could help me solve this word problem:\r
\n" ); document.write( "\n" ); document.write( "Two candles of the same height are lit at the same time. The first is consumed in four hours, the second in three hours. Assuming that each candle burns at a constant rate, how many hours after being lit was the first candle twice the height of the second?
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Algebra.Com's Answer #847015 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "CANDLE          BURN RATE      TIME         LENGTH of CANDLE\r\n" );
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document.write( "First           d/4             x             d-(d/4)x\r\n" );
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document.write( "Second          d/3             x             d-(d/3)x\r\n" );
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\n" ); document.write( "Question seems to need the \"length of candles\" to be as \"d-%28d%2F4%29x=2%28d-%28d%2F3%29x%29\".\r
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\n" ); document.write( "\n" ); document.write( "If divide left and right by d, then \"1-x%2F4=2%281-x%2F3%29\";\r
\n" ); document.write( "\n" ); document.write( "\"1-x%2F4=2-2x%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"-x%2F4=1-2x%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"2x%2F3-x%2F4=1\"\r
\n" ); document.write( "\n" ); document.write( "multiply left and right sides by 12;\r
\n" ); document.write( "\n" ); document.write( "\"8x-3x=12\"\r
\n" ); document.write( "\n" ); document.write( "\"5x=12\"\r
\n" ); document.write( "\n" ); document.write( "\"x=12%2F5\"
\n" ); document.write( "and this is 2 and two-fifths hours\r
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\n" ); document.write( "\n" ); document.write( "\"2%262%2F5=2%2624%2F60\" or two hours twenty-four minutes.
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