document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=116503>Question 116503</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of angles of a triangle is 180 degrees. The first angle is 12 degrees more than half the second angle. The third angle is 19 degrees less than 4 times the second angle. What is the measures of all three angles? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #84701 by </B><A HREF=/tutors/aboutme.mpl?userid=princess08><B>princess08(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=princess08><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=84701\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the second angle.<BR>\n" );
document.write( "Let 12+(x/2) be the first angle.<BR>\n" );
document.write( "Let (4*x)-19 be the third angle.<BR>\n" );
document.write( "The sum of the angles of a triangle is 180 so,<BR>\n" );
document.write( "[12+(x/2)]+x+[(4*x)-19]=180.<BR>\n" );
document.write( "12+(x/2)+x+4x-19=180<BR>\n" );
document.write( "(x/2)+5x=187<BR>\n" );
document.write( "(x/2)+(10x/2)=187<BR>\n" );
document.write( "11x=187*2<BR>\n" );
document.write( "11x=374<BR>\n" );
document.write( "x=34.<BR>\n" );
document.write( "12+(x/2)=29.<BR>\n" );
document.write( "(4*x)-19=117.<BR>\n" );
document.write( "Thus, the angles are 29, 34, and 117. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );