document.write( "Question 1208625: A three digit number \"ABC\" is divided by the two digit number \"AC\". The quotient is 16 with no remainder. What is the largest possible number \"ABC\"? \n" ); document.write( "
Algebra.Com's Answer #846999 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The value of the 3-digit number ABC is 100A+10B+C. \n" ); document.write( "The value of the 2-digit number AC is 10A+C. \n" ); document.write( "The 3-digit number is 16 times the 2-digit number: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "B is a single-digit integer; A is a single-digit integer so 6A is an integer. That means 1.5C must be an integer, which means C is an even single-digit integer. \n" ); document.write( "Try different values of C in equation [1] to find which ones give single-digit values for B: \n" ); document.write( "C=0: B=6A so A=1 and B=6; ABC is 160. 160/16 = 10 so that solution is good \n" ); document.write( "C=2: B=6A+3 so A is 1 and B is 9; ABC is 192. 192/16 = 12 so that solution is good \n" ); document.write( "For larger values of C, B=6A+1.5C will make B no longer a single-digit integer, so there are no more solutions. \n" ); document.write( "The two numbers ABC that satisfy the given condition are 160 and 192. \n" ); document.write( "ANSWER: 192 \n" ); document.write( " \n" ); document.write( " |